2007-01-23 01:38:07 · 3 answers · asked by cutaxilliselem voxphilius adicus 1 in Science & Mathematics ➔ Mathematics
I was going to point out 121 also.
If you count 1, then the statement is correct. But that would be trivial, for all whole numbers are divisible by 1.
If you need further proof that not all composite numbers are divisible by 2 through 10, just take any prime number over 10 (such as 11, 13, 17, 37) and square it (or take it to any other power). The resulting number is composite where the only factors are itself, 1, and the prime number you chose. Nothing else below 10.
2007-01-23 01:45:21 · answer #1 · answered by Rev Kev 5 · 0⤊ 0⤋
No, no even close. Any product of primes over 10 (ex.: 11x13, 17²x29, 191x193x197x199, etc.) will be composite and not have a factor less than 10.
2007-01-23 10:22:21 · answer #2 · answered by Anonymous · 0⤊ 0⤋
not always. the number 121 is composite
11 x 11
2007-01-23 09:44:11 · answer #3 · answered by Ray 5 · 0⤊ 0⤋