If you mean cloning the gene to make streptomycin, then this would be lethal to the cell that gets it. If you mean the gene that provides streptomycin resistance, then the recipient will become become resistant if given enough time to express the gene.
2007-01-23 02:35:01
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answer #1
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answered by Anonymous
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This is a technique every biologist is familiar with. This is a very basic example, that will answer your question.
You have a gene you want to make many copies of and for reasons of your own, you have chosen this method.
You stick your gene onto a plasmid, along with an strep-resistant gene. You put the plasmind IN E.coli (A plasmid is a circular length of DNA with some genes on it. It kinda acts like a DVD, which we use to store genes when we put them into living organisms).
E.coli then sees the plasmid, and starts reading the genes on the plasmid (like putting a DVD into a computer). It will then start making strep-resistant protein.
This is done on a large scale - we take MANY plasmids and mix them with MANY E.coli cells. After, we nuke the plate with lots of streptomycin. The E.coli that absorbed the plasmid will be protected because they made the strep-resistant proteins. The E.coli that didn't get any plasmid die a horrible death (well, not that horrible!).
This way, we know that our plate is "pure", i.e. almost all the E.coli there have our plasmid, which has the gene we want. They replicate and replicate and suddenly we have a LOT of plasmids (think of this as a technique used to create thousands of DVDs very easily).
So to answer your question: If E.coli have the streptomyces gene, then they are NOT susceptible to streptomycin.
2007-01-23 09:35:12
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answer #2
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answered by Nikos 2
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E. coli is already susceptible to streptomycin unless it has a resistance gene.
2007-01-23 09:26:40
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answer #3
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answered by floundering penguins 5
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No because when gene expression occure ,during that time bacteria adopt own self against that molicule
2007-01-27 04:27:14
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answer #4
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answered by praveesh bhati 1
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