find the derivative of this function y = 3sq root sign 4x^2 + 1?

1 ⤊

please show detailed explantion

2007-01-22 23:30:02 · 2 answers · asked by Lisa C 1 in Science & Mathematics ➔ Mathematics

If I understand your writing,as 4x^2 +1 is always positive
sign(4x^2+1) =+1
so your function reduces to y =3 and its derivative is always ZERO

2007-01-22 23:55:15 · answer #1 · answered by santmann2002 7 · 0⤊ 0⤋

y = 3*(4x^2 +1)^.5

y' = [.5*3*(4x^2 +1)^(-.5)]*[8x]

2007-01-23 07:35:39 · answer #2 · answered by fcas80 7 · 1⤊ 0⤋