For the home described in exercise 15, if the roof is 7 m from peak to eave and the attic space is 3 m high at the peak, how long does each of the pieces of insulation need to be? Round to the nearest tenth.
2007-01-22 22:56:56 · 3 answers · asked by Pushpendra C 1 in Science & Mathematics ➔ Mathematics
Use Pythagoras' theorem. If a right angled triangle has a height of 3 and a hypotenuse (longest side) of 7, you can work out the length.
Phytagoras' theorem is a² + b² = c², where a and b are the height and length and c is the longest side.
The answer is between 6 and 7; you'll need to work it out for yourself.
2007-01-22 23:03:51 · answer #1 · answered by Ben C 2 · 1⤊ 0⤋
The peak to eave distance is the hypotenuse of the right triangle and the hight of 3 is one side from this you can calculate the other side using pythagorean theorum a^2 + b^2 = c^2, you will need to use algebra to solve the formula for b (the second side). Then remember, that is only one side of the house, you have to double its length to get the length of insulation
2007-01-23 07:17:42 · answer #2 · answered by startrektosnewenterpriselovethem 6 · 0⤊ 0⤋
We don't have exercise 15. Give a complete question.
2007-01-23 07:00:58 · answer #3 · answered by Northstar 7 · 1⤊ 1⤋