2007-01-22 20:23:31 · 14 answers · asked by Pushpendra C 1 in Science & Mathematics ➔ Mathematics
graph and you'll see they both lie on on x-axis...
so, it would be /X2 - X1/ = /4- (-3)/ = /7/ = 7
distance is 7..
2007-01-22 22:44:24 · answer #1 · answered by swas77 2 · 0⤊ 0⤋
7
2007-01-22 20:31:35 · answer #2 · answered by Bill P 1 · 0⤊ 0⤋
Distance Formula
d = √(x₂- x₁)² + (y₂- y₁)²
d = √[4 - (- 3)]² + (0 - 0)²
d = √[4 + 3]² + 0
d = √[7]²
d = 7
- - - - - - - - - -s-
2007-01-23 00:24:41 · answer #3 · answered by SAMUEL D 7 · 0⤊ 0⤋
distance = sqrt (x2-x1)^2+(y2-y1)^2
= sqrt (4-(-3))^2+(0-0)^2
= sqrt (4+3)^2+(0-0)^2
= sqrt (7)^2+(0)^2
= sqrt (49)+(0)
= sqrt 49
= 7Units
therefore,the distance between this pair of
points is 7 Units...
2007-01-23 00:14:46 · answer #4 · answered by Akshitha 5 · 0⤊ 0⤋
Since the y value is the same for both points just subtract the first x value from the second.
4 - (-3) = 4 + 3 = 7
2007-01-22 22:10:47 · answer #5 · answered by Northstar 7 · 0⤊ 0⤋
d= 4-(-3) =7
2007-01-22 22:10:41 · answer #6 · answered by santmann2002 7 · 0⤊ 0⤋
7 units
2007-01-22 23:46:15 · answer #7 · answered by Anonymous · 0⤊ 0⤋
the distance is 7
since both y coordinates are zero, both points fall on the x axis
4 - -3 = 7 so the points are 7 units away from each other
2007-01-22 20:29:33 · answer #8 · answered by Bill F 6 · 1⤊ 0⤋
distance = [(x2-x1 , y2-y1)]
= [(4 - (-3) , 0 - 0) ]
= [( 7, 0 )]
so, the distance is 7 at x axis
2007-01-22 20:54:37 · answer #9 · answered by Sir Jas 2 · 0⤊ 0⤋
dist=sqrt((x' - x)^2 + (y'-y)^2) = sqrt((4 - (-3))^2 + (0 - 0)^2)
dist = sqrt(7^2) = (7^2)^(1/2) = 7
2007-01-22 21:47:17 · answer #10 · answered by Anonymous · 0⤊ 0⤋