2007-01-22 17:29:45 · 12 answers · asked by Anonymous in Sports ➔ Football (American)
Booooo Colts. Never!
Who dat dat when I say who dat??? DA BEARS!
2007-01-22 17:34:44 · update #1
I think it would be awesome, but unfortunately, the management of the team would never allow something like that at the moment. But I still think it would be AWESOME.
2007-01-22 19:29:30 · answer #1 · answered by Bob Peppers 3 · 0⤊ 0⤋
The difference between the '85 Bears and these Bears is the '85 Bears knew they were going to win. All they didn't know was by how much they were goiing to win by. These Bears dont know how they Quaterback is going to play The D is good but sometimes they slack. The only sure thing the Bears have is a running game.
2007-01-23 01:53:27 · answer #2 · answered by Jeff M 2 · 0⤊ 0⤋
Only if they use live bears... anything is possible in the Superbowl right? Well except for a decent halftime show.
I'm gonna laugh when Manning chokes.
2007-01-23 01:34:14 · answer #3 · answered by Anonymous · 1⤊ 1⤋
The shuffle was horrible in '85 and it would be even worse now.
2007-01-23 01:51:10 · answer #4 · answered by bucksbeat 2 · 0⤊ 0⤋
Heck it only took them 21 years to get back in the Super Bowl. Yeah they might as well.
2007-01-23 01:37:25 · answer #5 · answered by John71 3 · 1⤊ 0⤋
no , superbowl shuffle was like the team & its members all unique & many personalities. I still have that 45rpm disc. thereis
is no "unique" personalities this year
2007-01-23 01:54:31 · answer #6 · answered by CBO 2 · 0⤊ 0⤋
They should do what they want. That dance will only last for 2 weeks anyways.
2007-01-23 01:56:22 · answer #7 · answered by Anonymous · 0⤊ 0⤋
friends of pro athletes dont let pro athletes make music videos.
2007-01-23 01:34:03 · answer #8 · answered by dr schmitty 7 · 1⤊ 0⤋
they have to win it first......the only shuffling they'll do is when they go home and the Colts go to DisneyLand!
2007-01-23 01:32:58 · answer #9 · answered by Mr. Sir 5 · 0⤊ 1⤋
one is more enough
2007-01-23 01:39:17 · answer #10 · answered by Anonymous · 1⤊ 1⤋