N2 + 3H2 ---> 2NH3
You have to pick one to start off balancing with...since the H3 in NH3 is going to cause the trouble we should pick N2 or H2. N2 is already higher than the N in NH3 so H2 is the smart choice. You need this to be a multiple of the H3 in NH3. Because of this, we choose a multiple of 3.
Now we are too high on the H2 on the left side and 1 short on N on the right. So we change the multiple of this to 2 and everything is balanced!
To make sure we are correct:
Left Side:
N = 2
H = 6
Right Side:
N = 2
H = 6
That assures us that we are indeed correct.
2007-01-22 16:58:15
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answer #1
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answered by sdiver2489 4
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Balance N2 H2 Nh3
2017-01-12 08:26:47
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answer #2
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answered by ? 3
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First, balance the Nitrogen. Put 2 in the right (product) side. 2NH3 which balances N but now H has a total of 6.
Second, balance the Hydrogen. To get 6, you need to multiply H2 by 3, which makes it 6 or balanced.
Thus, N2 + 3H2 ---.> 2NH3
Then, always check your work by counting the number of atoms for each element. It will help you a lot in more complex chemical equations.
2007-01-22 17:00:48
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answer #3
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answered by Aldo 5
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3×2=6
2017-01-22 17:37:19
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answer #4
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answered by Sonia 1
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N2+3H2=2NH3
2007-01-22 17:01:40
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answer #5
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answered by alpha 7
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N2 + H2 ----> NH3
N2 + 3H2 ----> 2NH3
easy , make both sides equal
2 nitrogen on both sides
6 hydrogen on both sides
2007-01-22 17:01:50
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answer #6
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answered by Anonymous
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N2+3H2---------> 2NH3
2007-01-22 17:02:27
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answer #7
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answered by bindu 1
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3H2+N2 -> 2NH3
2007-01-22 17:00:35
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answer #8
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answered by Anonymous
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