can you help me with this math problem?

Question

a box contains 210 marbles which are either red or blue. there are 12 more red marbles than blue marbles. how many red marbles are in the box?

i need 2 show work

Answer 1

210-12=198
198 divide by 2=99
Blue marbles=99
Red marbles=99+12=111
easy

Answer 2

Let r = the number of red marbles
and b = the number of blue marbles

"a box contains 210 marbles which are either red or blue" tells you that: r+b = 210

"there are 12 more red marbles than blue marbles" tells you that: r = b+12

Combining the two equations you get r = 111, b = 99

Answer 3

210 / 2 = 105
105 - 12 = 93 blue marbles (44% @ 93 divided by 210)
105 + 12 = 117 red marbles (56% @ 117 divided by 210)

93+117 = 210 marbles with 117 red marbles in the box.

Answer 4

210 marbels - 12 red marbles = 198 marbles
198 marbles / 2 = 99 marbles
therefore 198 marbles = 99 blue marbles & 99 red marbles
99 red marbles+12 red marbles =111red marbles

Answer 5

first lets give a variable to each marble:

red = X
blue = Y

now we have to put them on a system of equations:

x + y = 210
x - y = 12

now that you got the system of equations you have to sole it which there are many different ways to do that. I will use elimination since its the easiest in this case.

x + y = 210
+ x - y = 12
------------------------
2x = 222
x = 111

there 111 red marbles and all you have to do to is to subtract it from 210 to get the answer for blue marbles which is 99.

Answer 6

well again over thinking, 210 Mable's divide by 2 then add 6 (that is half of 12) so assume average is equal then there should be
111 red and 99 blue.

Answer 7

let x r blue
then x+12 r red
total x+(x+12)=210
2x+12=210
2x=198
x=99
so no of blue is 99 and no of red is 111