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Heres the problem:
Peform the indicated operations. Express the answers in simplest form. Assume that no denominators is zero.
(5x-3)(4x+3)
I think that it's already in its simplest form. Any solutions?

2007-01-22 15:44:52 · 8 answers · asked by z1 2 in Science & Mathematics Mathematics

8 answers

The indicated operation here is multiplication: multiply the two binomials together.

(5x-3) * (4x+3)
20x^2 + 15x - 12x - 9
20x^2 + 3x - 9.

I think that's where you are supposed to go. Good luck.

2007-01-22 15:49:28 · answer #1 · answered by Tim P. 5 · 0 0

You need to multiply the two polynomials together using the FOIL Method [First, outside, inside last].
1. Multiply the first term in each set of parentheses
5x times 4x= 20(x^2), or twenty x squared
2. Multiply the outside terms together
5x times 3= 15x
3. Multiply the inside terms together
-3 times 4x= -12x (don't forget to include negative signs,
(5x-3) is equal to (5x+ -3)
4. Multiply the last terms together
-3 times 3= -9
5. Add everything together
20x^2 +15x+ -12x+ -9
6. Combine like terms
20x^2 +3x-9

2007-01-22 15:55:38 · answer #2 · answered by luckylivi11 1 · 0 0

x = 3/5 or -3/4

2007-01-22 15:48:59 · answer #3 · answered by daniel_156 2 · 0 0

the people after the first are wrong. You have it in the simplest factored form.

then just set each part to zero and solve. youll get 3/5 and -3/4 for X.

2007-01-22 15:52:42 · answer #4 · answered by Kyle M 6 · 0 0

(F)irst
(O)utside
(I)nside
(L)ast

FOIL!!!

This means we take 5x * 4x, the first two terms (20x^2), then the outside terms, 5x * 3 (20x^2 +15x), then inside, -3 * 4x (20x^2 + 15x -12x), and finally the last terms, -3 * 3, 20x^2 +15x - 12x - 9, or

20x^2 + 3x - 9

This is the equation in it's simplest form.

2007-01-22 15:50:59 · answer #5 · answered by Sean 2 · 0 0

(5x-3)(4x+3)
20x^2 (15x-12x)-9
20x^2 +3x-9

2007-01-22 15:55:10 · answer #6 · answered by daddyspanksalot 5 · 0 0

4 (2x+3)

2007-01-22 15:58:58 · answer #7 · answered by monica your new bff 3 · 0 0

20x^2+8x-9

2007-01-22 15:56:45 · answer #8 · answered by mary l 1 · 0 0

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