The indicated operation here is multiplication: multiply the two binomials together.
(5x-3) * (4x+3)
20x^2 + 15x - 12x - 9
20x^2 + 3x - 9.
I think that's where you are supposed to go. Good luck.
2007-01-22 15:49:28
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answer #1
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answered by Tim P. 5
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You need to multiply the two polynomials together using the FOIL Method [First, outside, inside last].
1. Multiply the first term in each set of parentheses
5x times 4x= 20(x^2), or twenty x squared
2. Multiply the outside terms together
5x times 3= 15x
3. Multiply the inside terms together
-3 times 4x= -12x (don't forget to include negative signs,
(5x-3) is equal to (5x+ -3)
4. Multiply the last terms together
-3 times 3= -9
5. Add everything together
20x^2 +15x+ -12x+ -9
6. Combine like terms
20x^2 +3x-9
2007-01-22 15:55:38
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answer #2
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answered by luckylivi11 1
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x = 3/5 or -3/4
2007-01-22 15:48:59
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answer #3
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answered by daniel_156 2
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the people after the first are wrong. You have it in the simplest factored form.
then just set each part to zero and solve. youll get 3/5 and -3/4 for X.
2007-01-22 15:52:42
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answer #4
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answered by Kyle M 6
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(F)irst
(O)utside
(I)nside
(L)ast
FOIL!!!
This means we take 5x * 4x, the first two terms (20x^2), then the outside terms, 5x * 3 (20x^2 +15x), then inside, -3 * 4x (20x^2 + 15x -12x), and finally the last terms, -3 * 3, 20x^2 +15x - 12x - 9, or
20x^2 + 3x - 9
This is the equation in it's simplest form.
2007-01-22 15:50:59
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answer #5
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answered by Sean 2
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(5x-3)(4x+3)
20x^2 (15x-12x)-9
20x^2 +3x-9
2007-01-22 15:55:10
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answer #6
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answered by daddyspanksalot 5
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4 (2x+3)
2007-01-22 15:58:58
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answer #7
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answered by monica your new bff 3
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20x^2+8x-9
2007-01-22 15:56:45
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answer #8
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answered by mary l 1
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