i solved it and got
y= -6 +2x/3
is that solution rite?
2007-01-22 14:55:28 · 10 answers · asked by L0cA Ch!Ca 1 in Science & Mathematics ➔ Mathematics
no
2x -3y = 6
3y = -6 +2x
y= 2x/3 -2
2007-01-22 14:59:37 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Just replace the x in the second equation with its value 6 - 3y from the first equation. 12 - 6y - y = 10 -7y = - 2 y = 2/7 and since x = 6 - 3y x = 6 - 6/7 = 36/7 or 5 1/7 In some simultaneous equations, you can see a quick and easy substitution route to solving them. In others, you are better off going the elimination route.
2016-05-23 23:41:31 · answer #2 · answered by ? 4 · 0⤊ 0⤋
No that answer is incorrect.
To find the answer you need to put the y on one side and all the other variables on the other so it looks like -3y=-2x+6. The you need to make the y plain with no number in front of it so you divide both sides by -3. You remembered to divide the 2x by -3 not the 6. Your end result should be 2x/3+ -2=y.
2007-01-22 15:01:54 · answer #3 · answered by Liz 1 · 0⤊ 0⤋
First of all. to get a distinct solution for a 2 variable system of equations, you need atleast 2 equations.
To get a general solution, just bring all 'Y' terms to one side, the rest on the other side n divide the whole equation by the coefficient of the 'Y' term.
what u have written is right.. but its necessary to mention the solution as:
y = (2x-6)/3
or
y = 2x/3 - 2
where x belongs to the set of real numbers.
2007-01-22 15:07:12 · answer #4 · answered by Vishal P 1 · 0⤊ 0⤋
No-your answer is incorrect.
First: subtract "2x" from both sides....
2x - 2x - 3y = 6 - 2x
- 3y = 6 - 2x
Sec: isolate "y" on one side > divide each term by "-3"....
(- 3y/-3) = (6/-3) - (2/-3)x
y = -2 + (2/3)x
Third: write the equation in slope-intercept form > y = mx + b in which, the "x"variable is always first....
y = (2/3)x - 2
2007-01-22 15:35:05 · answer #5 · answered by ♪♥Annie♥♪ 6 · 0⤊ 0⤋
The solution of the given equation is
2x - 3y = 6 => y= -6/3 +2x/3
y = -2 + ( 2/3 ) x
y = 2 ( -1 + x/3 )
y = 2 ( x/3 - 1 )
Hence, in this case
y = 2 ( x/3 - 1 )
Thanks for asking.......
2007-01-22 15:06:45 · answer #6 · answered by Cool Sun 3 · 0⤊ 1⤋
(x/3)-(y/2)=1 divided by 6
(2x/3) -y=2 multiplied by 2
2x/3=2+y y to the other side
(2x/3) -2=y 2 to the other side
2007-01-22 15:04:43 · answer #7 · answered by pepita_88 3 · 0⤊ 0⤋
2x - 3y =6
-3y = 6 + 2x
-3y % -3 = 6 + 2x % -3 (I'm using % fo the divide sign)
y = -2/3x - 2
2007-01-22 15:01:39 · answer #8 · answered by Aleu_hearts_Prongs 2 · 0⤊ 1⤋
-3y= -2x+6
y= 2x/3 -2
No, you have to divide the 6 by -3 as well.
2007-01-22 14:59:44 · answer #9 · answered by Anonymous · 0⤊ 0⤋
no... im in algebra and what you do is plug in zero for x so you get 0x-3y=6 so y is equal to -2
2007-01-22 15:00:05 · answer #10 · answered by ilikeguitar 1 · 0⤊ 1⤋