what will be the volume at 800 mm Hg?
2007-01-22 14:51:16 · 4 answers · asked by lhyne d 1 in Science & Mathematics ➔ Chemistry
Use conversion factors of atmospheric pressure as well as that of mL and L. I'd solve it but I've got to go! Good Luck!!!
Is this general Chem or AP Chem by the way?
2007-01-22 14:55:23 · answer #1 · answered by étoile 2 · 0⤊ 0⤋
Use the equation P(1)V(1)=P(2)V(2)
so:
(740mmHg) (15.0 L) = (800 mm Hg) ( ? L)
(740mmHg) (15.0 L) /(800 mm Hg) = ? L
L = 13.875
In sig figs: 14 L
*** for the post above : you do not need conversion factors if you are dealing with the same units in this type of equation.
2007-01-22 22:55:57 · answer #2 · answered by meanest_pianist 2 · 0⤊ 0⤋
Volume and pressure are inversely proportional by the Ideal Gas Law, so as pressure increases at constant temperature, volume will decrease.
If you use two different states, then you will get:
P(1)V(1) = nRT = P(2)V(2)
Solve for V(2) which will be P(1)V(1)/P(2), or 740*15/800 or 13.9 L.
2007-01-22 22:59:32 · answer #3 · answered by TheOnlyBeldin 7 · 0⤊ 0⤋
use P1V1=P2V2...........REARRANGE to......P1V1/ P2=V2
P1=740 MM HG P2=800
V1=15.0 L so
(740 mm hg0)*(15.0)/(800 mm hg)=13.875 L
2007-01-22 22:59:03 · answer #4 · answered by bob m 2 · 0⤊ 0⤋