quadratic form help please?!?!?!?

Question

i need help solving this heres the question???
write f(x)=-2+(x-5)2 please show work or at least explain it 2 me

HELP PLEASE?!?!?!?

Answer 1

Developed by Alex Casciani at NYOC.net.
X^-1 = x to the negative first power
X^1 = x to the first power


Turn on calculator AND FOLLOW DIRECTIONS. Just hit buttons, nothing else!
PRGM
(blue right arrow on the right of calculator) ►
(blue right arrow on the right of calculator) ►
ENTER
9
5
MATH
X^-1
ENTER

PRGM
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ENTER
2nd
ALPHA
+
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LOG
7
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PRGM
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ENTER
2ND
ALPHA
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MATH
(-)
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PRGM
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ENTER
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ALPHA
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APPS
(-)
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APPS
ENTER

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ENTER
2ND
ALPHA
+
PRGM
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PRGM
ENTER
ENTER

PRGM
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ENTER
2ND
ALPHA
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SIN
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X^2
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X^2
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MATH
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STO►
ALPHA
4
ENTER

PRGM
(blue right arrow on the right of calculator) ►
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(blue down arrow on the right of calculator) ▼
ENTER
ALPHA
4
ENTER

PRGM
(blue right arrow on the right of calculator) ►
(blue down arrow on the right of calculator) ▼
(blue down arrow on the right of calculator) ▼
ENTER
2ND
ALPHA
+
0
+
ENTER

PRGM
(blue right arrow on the right of calculator) ►
(blue down arrow on the right of calculator) ▼
(blue down arrow on the right of calculator) ▼
ENTER
2ND
ALPHA
+
LN
SIN
4
0
ALPHA
2
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+
ENTER
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(-)
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APPS
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2ND
X^2
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X^2
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MATH
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)
)
÷
2
ALPHA
MATH
STO►
ALPHA
1
ENTER

PRGM
(blue right arrow on the right of calculator) ►
(blue down arrow on the right of calculator) ▼
(blue down arrow on the right of calculator) ▼
ENTER
ALPHA
1
ENTER

PRGM
(blue right arrow on the right of calculator) ►
(blue down arrow on the right of calculator) ▼
(blue down arrow on the right of calculator) ▼
ENTER
2ND
ALPHA
+
0
+
ENTER
ENTER

PRGM
(blue right arrow on the right of calculator) ►
(blue down arrow on the right of calculator) ▼
(blue down arrow on the right of calculator) ▼
ENTER
2ND
ALPHA
+
LN
7
)
5
4
X^2
7
LOG
0
LN
SIN
4
+
ENTER

PRGM
(blue right arrow on the right of calculator) ►
(blue down arrow on the right of calculator) ▼
(blue down arrow on the right of calculator) ▼
ENTER
2ND
(
ALPHA
1
,
ALPHA
4
2ND
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2ND
ON

ON
PRGM
Find the program called “QUAD” and highlight it
ENTER
ENTER
(for testing purposes use this equation: x^2 + 4x + 4
Under A? enter: the a value, which equals 1
Once you press 1 hit enter

Under B? enter: the b value, which equals 4
Once you press 4 hit enter

Under C? enter: the c value, which equals 4
Once you press 4 hit enter

Your solution set equals {-2 -2} or just {-2}

Once done, you can then press CLEAR and turn your calculator off!!!

Answer 2

f(x) = -2+ (x-5)^2
= -2 +(x-5)(x-5) Rewrite the square
=-2+ x^2-5x-5x+25 First, inside, outside, last
= x^2 -10x +23 Simplify

Answer 3

ax^2 + by skill of^2 +2xy (say) = c the place a,b,c are constants and x,y variables. you have 2 variables and one eqaution. the uncomplicated rule of arithmetic is that, you're able to desire to have an quantity of equations that fits the variety of variables. using quadratic form is that whether you have purely one variable and a quadratic equation, there's a answer for the variable. the variable could have 2 strategies maximum. further, in case you have had 2 quadratic equations for the two variables, you're transforming into have been given strategies for the two the variables to a maximum no of two each and each, offering a sequence of four strategies.

Answer 4

When asking a question involving the number 2, it is a good idea NOT TO substitute the number 2 for the word "to"; as it makes a person uncertain where the actual math problem ends and your question about the problem starts.

Answer 5

f(x)= -2+(X-5)^2
= -2+(X^2-10X+25)
= X^2-10X+23.. this is the quadratic form

To do this, first apply the formula:
(a-b)^2= a^2-2ab+b^2
next, open up the brackets and simplify the expression.

Answer 6

f(x)=x(squared)-10x+23

10+or- Square root of (100-(23*4*1), all over 2

10+ or - 2, all divided by 2

6 and 4 are the answers.

Answer 7

f(x)=-2+(x-5)2
It should have been written as : f(x)=-2+(x-5)^2, This can be written as : f(x)=-2+(x-5)^2 = 2 + x^2 - 10x + 25
= x^2 - 10x + 27 Answer.

Answer 8

f(x) = -2 + (x - 5)^2

To put this in standard form, you have to expand (x - 5)^2. Just to remind you, this is he same as:

f(x) = -2 + (x - 5)(x - 5)

Now, expand,

f(x) = -2 + (x^2 - 5x - 5x + 25)

Now, simplify

f(x) = -2 + x^2 - 10x + 25

And simplify again, this time ensuring our terms is in descending power of x.

f(x) = x^2 - 10x + 23

Answer 9

right you have that equation.

(x-5)^2 is the same as

(x-5)(x-5)

Then you do x multiply x
-5 multiply x
-5 multiply x
-5 multiply -5

then group them giving

x^2 -10x + 25 then just add -2 giving

x^2 - 10x + 23