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x^2 - 5x - 36 / 3x^2 (times) 9x/5x - 45

2007-01-22 14:34:52 · 2 answers · asked by Antonello D 1 in Science & Mathematics Mathematics

2 answers

((x^2 - 5x - 36) / 3x^2) (9x/(5x - 45)
= ((x - 9)(x + 4)/x)(3/5(x - 9)
= (3(x + 4)/(5x((x - 9))
=(3x +12)/

2007-01-22 16:25:18 · answer #1 · answered by tablecloth 1 · 0 0

((x^2 - 5x - 36) / 3x^2)(9x/(5x - 45) =
((x - 9)(x + 4)/x)(3/5(x - 9) =
(3(x + 4)/(5x((x - 9))

2007-01-22 22:49:54 · answer #2 · answered by Helmut 7 · 0 0

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