3/7y - 3 + 3 = 4 + 3 (add +3 to both sides)
3/7y = 7
(7/3) * 3/7 * y = (7/3) * 7 (multiply both sides by 7/3 to clear the y)
y = 49/3
Proof
3/7y - 3 = 4 (start with the original formula)
3/7 * (49/3) - 3 = 4 (substitute 49/3 for y)
7 - 3 = 4 (solve)
4 = 4 Proved
2007-01-22 14:25:18
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answer #1
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answered by The Answer Man 5
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y =3
2007-01-22 22:27:34
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answer #2
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answered by Deb 1
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For starters, I'm sure the community would appreciate if you put a bit more into your question, such as, "Could someone please help me solve this math problem for homework?" and then give it. Now, to the problem. You need to isolate Y by itself, so you add three to both sides so that you end up with...
3/7y=7
...then you multiply 3/7y by 7/3y so you get one y. (Remember, if you multiply by its reciprocal, the two cancel out as one) Then you multiply 7 by 7/3 also and you get y=49/3.
Hope I didn't make a mistake somewhere...but I don't see how I could have.
2007-01-22 22:26:10
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answer #3
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answered by fslcaptain737 4
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3/7y - 3 = 4
+3 = +3
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3/7y = 7
------ ---
3/7 3/7
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y = ?
so divide 7 by 3/7
Good Luck!
I am not going to tell you the whole answer, but there is a start!
2007-01-22 22:28:47
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answer #4
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answered by O 3
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y = 49/3
(3/7y = 7)
(7x7/3=y)
(49/3=y)
2007-01-22 22:24:54
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answer #5
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answered by christie m. 2
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