HELP WITH MY mATH!!?

Question

What number do u start off with if u had to subtract 2, divide by 5, add 7, multiply by 3, and your result equals 30???

Answer 1

((x-2)/5 + 7)*3=30
(x-2)/5 + 7 = 10
(x-2)/5 = 3
x-2 = 15
x=17

Answer 2

17;

Set up the equation:

3*(((X-2)/5)+7)=30
Solve for X
by:
1. Dividing 30 by 3 = 10
2. Subtracting 7 from ten = 3
3. Multiplying 3 by 5 = 15
4. Adding 2 to 15 = 17

Answer 3

The answer is 17. 17-2=15/5=3+7=10*3=30

Answer 4

All you have to do is work the problem backwards and do the opposite of what you are supposed to do. start with 30 divide by 3 with is 10. subtract 7 =3. multiply by 5 then you have 15 and then add 2. your answer is going to be 17

Answer 5

Work backwards. x=divide -=+

30 divide 3 - 7 x 5 + 2 = 10 - 35 + 2 = -27

Answer 6

To solve this you go backwards. 30/3=10, 10-7=3, 3*5=15, 15+2=17. The answer is 17.

Answer 7

17

Answer 8

17

Answer 9

Write and solve an equation:

[(x-2)/5 + 7]•3 = 30
(x-2)/5 + 7 = 10
(x-2)/5 = 3
x - 2 = 15
x = 17

Answer 10

There are 2 ways to interpret your question

1) using standard 4 operation (which you have to do the x and / first)

__ - 2 / 5 + 7 x 3 = 30

__ - 0.4 + 21 = 30

__ = 30 + 0.4 - 21

= 9.4


2) You placed comma in each operation, so we assume you want it step by step. We can do a reverse caculation (e.g add become minus, x become /, etc when u reverse the equation)

30 / 3 = 10
10 - 7 = 3
3 x 5 = 15
15 + 2 = 17

So, which way your question is asked?

Answer 11

17