Simplify the expression (7x/5x+3)-(6/5x^2+3x)+(2/x)?

Question

I can't figure this out! Please help. Thank you

Answer 1

This boils down to finding common denominators. Take the first two - the denominators are 5x + 3 and 5x^2 + 3x. The LCD of the two is 5x^2 + 3x, and to make the first fraction's denominator look like the second, you would have to multiply by x. So your first fraction would end up looking like (7x^2)/(5x^2 + 3x).

Likewise for the second and third - the LCD is also 5x^2 + 3x, and you would get the third's denominator to look like the second by multiplying by 5x + 3. So the third would look like (10x + 6)/(5x^2 + 3x).

Now that all the denominators are the same, just combine the numerators:

(7x^2) - (6) + (10x + 6) = 7x^2 + 10x

And your denominator would be what we had in the first place, 5x^2 + 3x. So your combined expression would be:

(7x^2 + 10x)/(5x^2 + 3x)

You could (and should) go a step further and reduce this - there is an x common in both the numerator and denominator, so eliminating that would leave you with

(7x + 10)/(5x + 3)

Answer 2

If the 2s on your equation are exponents, then Jun Agruda is right. If the 2s are multipliers then examine is right. convention tells us that in case you elect to precise exponents, you are able to desire to incorporate a carat, ^, until eventually now the exponent. as an occasion: (3s + a million)^2. Multipliers are in many circumstances placed until eventually now the article to be more advantageous. Absence of the carat shows that multiplication is indicated somewhat than squaring that's a style of multiplying.