Michael is pushing his car of 1.5kg at .5m/s2(squared, the two is an exponent, the power of 2) , to a distance of 5 m. How much force is he putting? How much work? When solving this can you show me the steps of problem solving and then the answer?
2007-01-22 14:08:51 · 2 answers · asked by i am what i am 2 in Science & Mathematics ➔ Physics
It must be a toy car if it only weighs 1.5 kg.
The way to write 'squared' is to use the carat symbol: 0.5 m/s^2, and the square root of x is written x^(1/2) or sqrt(x).
M/S^2 means the car is accelerating while he's pushing it, so you can use the distance formula s=1/2 * a * t^2 with s=5=0.25*t^2. Therefore t^2 = 5/0.25 = 20, and t=sqrt(20)=4.5 seconds.
Force = mass * acceleration = 1.5 * 0.5 = 0.75 kg-m/s^2.
Work = force * distance = 0.75 * 5 = 3.75 kg-m^2 / s^2.
2007-01-22 14:31:52 · answer #1 · answered by hznfrst 6 · 0⤊ 0⤋
Using your convention of s2 = s squared, and * is a multiply sign:
Work = Force * distance, and Force = mass * acceleration. Thus, work = mass * acceleration * distance, or 1.5kg * 0.5m/s2 * 5m = 3.75 kg*m*m/s2 or 3.75 newton-meters.
(Newton = kg*m/s2)
2007-01-22 22:21:58 · answer #2 · answered by bobo383 3 · 0⤊ 0⤋