can someone show me the best way to solve these prombles by either factoring, completing the square, or the quadratic formula.
many thanks!!
2007-01-22 13:05:37 · 3 answers · asked by Zac 2 in Science & Mathematics ➔ Mathematics
For the second one: Using factoring: (5x+7)(3x-1)
2007-01-22 13:11:04 · answer #1 · answered by asphyxia 3 · 0⤊ 0⤋
a million. bear in techniques that with absolute fee there are (exceedingly much) constantly 2 possibilities. in this occasion the two probability is: -2x + 3 = x - 15 and -2x + 3 = - (x - 15) = -x + 15 fixing each and every , we get: x = 6 or x = -12
2016-12-16 11:05:26 · answer #2 · answered by ? 4 · 0⤊ 0⤋
x^2 + x - 42 = 0
(x+7)(x-6)=0
x+7=0
x=-7
x-6=0
x=6
x= 6, -7
15x^2 + 16x - 7 = 0
(3x-1)(5x+7)=0
3x-1=0
x=1/3
5x+7=0
x=-1.4
x=1/3, -7/5
2007-01-22 13:11:17 · answer #3 · answered by yupchagee 7 · 0⤊ 0⤋