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How many grams of NaAlO2 can be obtained from 4.46 g of AlCl3 according to the following reaction?

AlCl3(aq) + 4NaOH(aq) →
NaAlO2 (aq) + 3NaCl(aq) +2H2O(l)

2007-01-22 12:57:08 · 1 answers · asked by San Fran Kid 2 in Science & Mathematics Chemistry

1 answers

This would be a mass-mass stoichiometry problem. Take the mass of AlCl3 given divided by the molar mass of AlCl3, then multiply it times the mole ratio of NaAlO2 to AlCl3 from your balanced equation, and then times the molar mass of NaAlO2.

4.46 g AlCl3 / 133.3 g/mol AlCl3 x 1 NaAlO2/ 1 AlCl3 x 81.97 g/mol NaAlO2 = 2.74 g NaAlO2

2007-01-22 16:25:22 · answer #1 · answered by Mrs. F 2 · 0 0

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