plese help, due tomorrow!
2007-01-22 12:17:44 · 3 answers · asked by abercombie123 1 in Science & Mathematics ➔ Biology
Ach, they are both wrong. Well, right and wrong. With codominance you can produce a different phenotype for the heterozygote. But with only TWO alleles (not 3 gentlemen) you can only have THREE phenotypes: AA, AB, BB for example.
No, two alleles cannot produce four phenotypes. There aren't enough combinations.
2007-01-23 01:54:53 · answer #1 · answered by floundering penguins 5 · 0⤊ 1⤋
With codominance, both alleles produce and effective product. ... As a result, there are four possible phenotypes or blood types: A, B, AB, and O. ...
2007-01-22 12:23:22 · answer #2 · answered by joe m 1 · 1⤊ 1⤋
joe m is 100% correct, however if you are trying to understand this further i would suggest doing a Punnett square. cross a heterozygous A with a heterozygous B. aka Ai x Bi
If you get Ai or Bi in the cross then you have either type A or B blood repectively. If you get ii, you have no markers so it is type O blood, the universal donor, and if you get AB you have type AB blood, the universal acceptor.
Hope this helps clarify.
2007-01-22 12:26:39 · answer #3 · answered by Sir Smith 2 · 1⤊ 1⤋