A rolling ball has an initial velocity of -1.5 m/s. If the ball has a constant acceleration of -0.23 m/s^2, what is its velocity after 2.2s?
What is the average velocity during the time interval? How far did it travel in this time interval?
Please let me know how to get the answers to these. I need to learn. Thank you.
2007-01-22 10:50:44 · 4 answers · asked by rcpaden 5 in Science & Mathematics ➔ Physics
I am a homeschool mom trying to teach my son from a terrible curriculium. We would just change curriculiums but all my son is almost done with all 23 credits.
2007-01-23 00:46:17 · update #1
Use the formula V=Vo+at
initial velocity or Vo=-1.5m/s
a=-0.23m/s^2
t=2.2s
plug them in V=-1.5+(-0.23x2.2)
V=-2.006
I don't know the rest but i hop that this was helpful!
2007-01-22 12:46:23 · answer #1 · answered by Iamhere 4 · 0⤊ 0⤋
Add the change in velocity (-0.23 x 2.2) to the initial velocity (-1.5) to get the final velocity. Pretty simple; they get harder.
2007-01-22 18:56:09 · answer #2 · answered by Anonymous · 0⤊ 0⤋
the new velocity is equal to the original velocity plus 0.5 * acceleration * time * time.
2007-01-22 18:55:54 · answer #3 · answered by Anonymous · 0⤊ 0⤋
yep, ask your teacher
2007-01-22 19:00:01 · answer #4 · answered by chicago cub's bat bunny 5 · 0⤊ 1⤋