Two small silver spheres, each with a mass of 13.0 g, are separated by 1.00 m. Calculate the fraction of the e

Answer 1

I will assume the silver spheres are much much smaller than the distance between them so they can be treated as point particles.

The magnitude of the electrostatic force between two point particles is given by:

F = k*|q1|*|q2|/R^2

where k is the electrostatic constant = 8.988*10^9 (N*m^2)/C^2
|q1| and |q2| are the absolute values of the charges on particles 1 and 2 (in coulombs)
R is the distance between the particles (in meters)

Because we are transferring charge between the two particles in this case, q1 = -q2, so the above eqation simplifies to:

F = (k*q^2)/R^2

Plug in the distance and desired force and solve for q:

2*10^4 N = [q^2 * 8.988*10^9 (N*m^2)/C^2]/(1 m)^2

q^2 = 2.233*10^-6 C^2

q = 1.491*10^-3 C

One coulomb equals is the amount of electrical charge in 6.2415×10^18 electrons so

1.491*10^-3 C * 6.2415×10^18 electrons/C = 9.305*10^15 electrons must be transferred from one particle to the other.

The atomic mass of silver is 107.868 gm/mol, so a 13 gm Ag sphere contains 13 gm /107.868 gm/mol = 0.121 mol of Ag. There are an Avagadro's number of silver atoms in a mole, and each atom has 47 electrons, so when the spheres are electrically uncharged, each sphere contains:

(13 gm/107.868 gm/mol) * 6.022*10^23 atoms/mol * 47 electrons/atom = 3.411*10^24 electrons

The fraction of electrons in one sphere that must be transferred is then:

(9.305*10^15)/(3.411*10^24) = 2.728*10^-9

Answer 2

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Answer 3

What is e?