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A man weighing 200 pounds and 2 boys weighing 100 pounds need to cross a river. The only boat that is available will only carry 200 pounds. How can they cross the river using only the boat they have to carry them across?

2007-01-22 08:18:30 · 9 answers · asked by ? 2 in Entertainment & Music Polls & Surveys

9 answers

200 lb guy puts the 2 boys in boat and he swims on the side of boat till they get across

2007-01-22 08:26:26 · answer #1 · answered by Sweetness 5 · 0 0

first go the two boys
the one returns with the boat
then the fat man goes alone to the other side
the boy which has alreday crosssed the river takes the boat and goes back and then the two boys cross the river together

2007-01-22 16:24:48 · answer #2 · answered by girl24gr 3 · 0 0

"Puzzle" is spelled "Puzzle"
(This is assuming that there's no way to ferry the boat back to the other side of the river empty)

(1) Both boys go across (200 lbs)
(2) one boy goes back (100 lbs)
(3) 200 lb guy goes across (200 lbs)
(3) other boy goes back (100 lbs) to retrieve first boy
(4) Both boys cross.

2007-01-22 16:22:52 · answer #3 · answered by Perdendosi 7 · 0 0

The 200 pound man gets in the boat and the two boys swim beside it??????????

2007-01-22 16:24:28 · answer #4 · answered by running2adream 6 · 0 0

Um they ride the man across the river?

2007-01-22 16:23:46 · answer #5 · answered by qųěęŋ ŏf ħęãŗţş 3 · 0 0

the two boys go across, one comes back and lets the man go across, then the boy who already crossed goes back to get the other boy...

2007-01-22 16:24:22 · answer #6 · answered by sammiejane67 4 · 0 0

Depends on how deep the river is. Maybe they all walk across.

2007-01-22 16:34:15 · answer #7 · answered by tiffantre 3 · 0 0

first the boys cross, leaving one on the other shore, the other returns, gets out, and the man crosses, gets out, then that boy gets back in, recrosses to pick up the other boy...

2007-01-22 16:23:33 · answer #8 · answered by Anonymous · 1 0

cut the man in half

2007-01-22 16:33:09 · answer #9 · answered by manson1 2 · 0 0

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