Chemistry Help Please?

Question

When 14.28mL of 2.92 M HCL are added to 15ml of 3.07 M NaOH, a measurement shows that 2.35 kJ of heat are released. Calculate the heat of neutralization in kJ/mol

Answer 1

HCl + NaOH ==> NaCl + H2O

0.01428L x 2.92 mol/L = 0.0417 mol
0.015L x 3.07 mol/L = 0.0460 mol
HCl Limits the neutralization to 0.0416 mol

2.35kJ/0.0417mol = 56.4 kJ/mol