2007-01-22 04:18:29 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
"If" is suppose to be Of
2007-01-22 04:19:24 · update #1
you have two basic solutions, 1) x=0 2) y=0
1) 5*0-y=1 ==> y=(-1) ==>(0,-1)
2) 5*x-0=1 ==> x=(1/5) ==>(1/5,0)
reall there are an infinite number of solutions if you graph it out
y=5x-1. Since the equation is continuous for (-INF,+INF), there are infinite solutions that satisfy this equation.
2007-01-22 04:27:35 · answer #1 · answered by Anonymous · 0⤊ 0⤋
rewrite
y=5x-1 and give values to x
example if x=7 y= 5*7 -1 =34
2007-01-22 04:31:11 · answer #2 · answered by santmann2002 7 · 0⤊ 0⤋
there will be an infinite number of solutions. Rewrite the equation in slope-intercept form and substitute values in for x and that will give you your ordered pairs.
2007-01-22 05:33:33 · answer #3 · answered by Ray 5 · 0⤊ 0⤋
re arrange your equation to
y = 5x - 1
Pick your x and figure out the y using the equation
(x=0 , y = -1)
(1, 4)
etc...
2007-01-22 04:25:30 · answer #4 · answered by CAM1122 3 · 0⤊ 0⤋
infinite pairs exists a straight line
a few part may be discovered by simplle puttting any x and solving y
eg at x=0 we get y= -1 etc...............
2007-01-22 04:28:33 · answer #5 · answered by agarwalsankalp 2 · 0⤊ 0⤋
Solve it for 'y', plug a value of your choosing for 'x', find 'y', and that's one ordfered pair.
Repeat to find another one.
2007-01-22 04:28:29 · answer #6 · answered by Anonymous · 0⤊ 0⤋