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Can someone help me with Polynomial Long Division.

Divide. Express your answer as a polynomial or mixed expression.

1. n^2 - 11n - 26 / n+2

2. s + s^2 - 8 / s+4


Thanks so much. and if you could show me how you arrived to the answer that would be helpful. Thanks SOOO much.

2007-01-22 03:54:06 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

The question is how to do long division -- not how to factor.
1. n^2 - 11n - 26 / n+2
n^2 -11n -26 is the dividend and (x=2) is the divisor. The result of the division is called the quotient.

Take 1st term of the divisor and divide it into 1st term of the dividend. This gives n^2/n = n which is the 1st term in the quotient.

Now multiply the partial quotient by the divisor getting n(n+2)=
n^2+2n. Now place the n^2 + 2n directly below the n^2 - 11n of the dividend and subtract. You should get -13n. Bring down the
-26 so you have -13n -26.

Now divide this result by the 1st term of the divisor getting
-13n/13 = -13. Add this to the partial quotient so quatient is now n-13. Now multiply the -13 times the divisor getting -13n - 26

Place the this -13 -26 directly below the -13 - 26 obtained in the previous step and subtract. You will get zero.

This means that n-13 is the quotient and there is no remainder.

It is difficult to explain this without just showing the work but it is hard to align things so they make sense.

Hope you could understand this and will be able to apply it to the second problem.

2007-01-22 04:27:20 · answer #1 · answered by ironduke8159 7 · 1 1

(n^2 -11n -26)/(n+2) = (n+2)*(n-13)/(n+2)= n-13

s^2 +s -8 /s+4 = s -3
-4s
-3s -8
+12
4


(s^2 +s -8)/(s+4 ) = s-3 + 4/(s+4)

2007-01-22 12:15:58 · answer #2 · answered by santmann2002 7 · 0 1

1) factor.
(n+2)(n-13)/(n+2) = n-13

2007-01-22 12:01:53 · answer #3 · answered by ENA 2 · 1 1

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