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2 answers

(cd-2)3 over c4d9)-2
= (cd^{-2})^3 / (c^4 d^9)^{-2}
= c^3 d^{-6} / c^{-8} d^{-18}
= c^11 d^12 .

2007-01-22 06:40:30 · answer #1 · answered by Anonymous · 0 0

(cd)^-6 divided by c^-8d^-18
subtracting the exponents in the demonator from the exponenets in the numerator
leads to c^2d^12

2007-01-22 04:00:22 · answer #2 · answered by physical 4 · 0 0

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