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(4)^2
------ -(4)
(-2)^3

and

(-8)^2 + (4)^2
--------
(-8)

2007-01-22 03:11:15 · 3 answers · asked by Brent S 1 in Science & Mathematics Mathematics

3 answers

1) =16/(-8) -4 = -6

2)= 64/(-8) +16 = -8+16=8

2007-01-22 03:20:01 · answer #1 · answered by santmann2002 7 · 0 0

I agree with the answer given for the first problem. -6
However, I think the reason these two problems were given to you together was to show how to handle the addition/subtraction differently for each problem.
The first problem has you dividing and then subtracting 4 from that quotient.
The second problem has you adding +4^2 in the denominator. The order of operations says that you perform operations on parentheses first. But 'parentheses' in the PEMDAS mnemonic (Parentheses,Exponent,Multiplication and Division, Addition and Subtraction) includes several other things that group terms: for example, brackets and the fraction bar. So you do everything in the numerator first because it is in a kind of 'parentheses' above the fraction bar. This means (-8^2 +4^2) = (64 + 16) = 80 is the numerator. This is divided by -8 so the result is -10.
Exponents is another term that includes something else - a radical expression is treated like an exponent in terms of order of operations.

2007-01-22 03:56:29 · answer #2 · answered by kathyw 7 · 0 0

4^2 = 2^4 so you obtain for the first -2-4 = -6

second : the fraction is equal to -8 4^2 =16
so for second -8+16 = 8

2007-01-22 03:22:20 · answer #3 · answered by maussy 7 · 0 0

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