a. p>-9
b.p<9
c.p>-5
d.p>5
2007-01-22 02:50:07 · 10 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
3p - 6 < 21
=> 3p < 21 + 6
=> 3p < 27
=> p < 27/3
=> p < 9
(b)
2007-01-22 03:29:08 · answer #1 · answered by Anonymous · 1⤊ 0⤋
The answer is A. you have to add 6 to both sides. the 6+6 would cancel and 6+21=27. Then you have to divide 27 by 3 and you get 9.
2016-05-24 17:43:51 · answer #2 · answered by Anonymous · 0⤊ 0⤋
3p-6<21 so 3p <27 and p< 9
b) is the right answer
2007-01-22 03:27:50 · answer #3 · answered by santmann2002 7 · 1⤊ 0⤋
3p < 27
p<9
2007-01-22 03:09:09 · answer #4 · answered by Anonymous · 1⤊ 0⤋
Add 6 from both sides:
3p<27
Divide 3 from both sides:
p<9
Check:
3(9)-6=21
27-6=21
21=21
The answer is b.
2007-01-22 03:27:37 · answer #5 · answered by Anonymous · 0⤊ 0⤋
3p-6<21
3p<27
p<9
b
2007-01-22 03:15:18 · answer #6 · answered by jaw_nerto 1 · 1⤊ 0⤋
add 6 to each side: 3p<27
divide each side by 3: p<9
thus.... your answer is p<9
2007-01-22 08:25:15 · answer #7 · answered by mark p 2 · 0⤊ 0⤋
b) p<9
3p-6 < 21
3p < 27
p < 9
2007-01-22 03:07:09 · answer #8 · answered by chemelle 2 · 2⤊ 0⤋
b
2007-01-22 07:15:09 · answer #9 · answered by Rudy T 1 · 0⤊ 0⤋
d
2007-01-22 04:05:40 · answer #10 · answered by omusonye 1 · 0⤊ 0⤋