let x be the number of student tickets sold.
therefore (812-x)=no. of non-students tickets sold.
total money received= 1912
therefore 1912= (812-x)(3) + (x)(2)
1912=2436-3x+2x
1912=2436-x
hence x=2436-1912
x=524
2007-01-22 03:06:45
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answer #1
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answered by jaw_nerto 1
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use simultaneous equations to solve.
Let x be the number of student tickets sold.
Let y be the number of non-student tickets told.
x + y = 812 .....(1) [the total number of tickets sold]
2x + 3y = 1912 .....(2) [the total amount of money received]
From (1):
2x + 2y = 1624 ..... (3) [multiply throughout by 2]
(2) - (3):
y = 288
Subst. y = 288 into (1):
x + 288 = 812
x = 524
Therefore, 524 student tickets were sold.
2007-01-22 02:47:08
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answer #2
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answered by rfedrocks 3
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the number of student tickets that were sold were 524 and the no. of non student tickets were 288
let x be the no. students
and let y be the no.of non students
total no. of tickets sold=812= total no. studens who bought them
so, x+y=812
and $2 for students so amount paid by all students=2x
and $3 for students so amount paid by all non students=3x
but total amount that tickets were sold for= 1912
so 2x+3y=1912
solve the two equations
you will get the answer
2007-01-22 02:56:42
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answer #3
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answered by harsha 1
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2*x + 3*(812-x) = 1912
2436 - x = 1912
524 = x
524 $2 tickets
2007-01-22 02:47:08
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answer #4
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answered by xwdguy 6
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x student tickets were sold.
(812 - s) non-student tickets were sold.
The total sales were
2 * (student tickets) + 3 * (non-student tickets) = 1912
â 2x + 3(812 - x) = 1912
Solve for x!
2007-01-22 02:43:49
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answer #5
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answered by Anonymous
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# of students = x
# of non students = y
x + y = 812, x = 812 - y
2x + 3y = 1912
2(812 - y) + 3y = 1912
1624 + y = 1912
y = 288
x = 524
524 Student tickets sold.
2007-01-22 02:44:34
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answer #6
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answered by p_rutherford2003 5
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x=the students paid per ticket
y=the non-students paid per ticket
x+y=812
2x+3y=1,912
-3x-3y=-2436
2x+3y=1,912
==========
-x=-524
x=524
524+y=812
y=288
524 tickets were sold to students and 288 tickets were sold to non-students.
I hope this helps!
2007-01-22 03:32:58
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answer #7
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answered by Anonymous
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