solve
2007-01-22 01:29:19 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
In general:
ln(a)-ln(b)=ln(a/b)
Here:
ln(x)-ln(x-11)=ln(3)
<=> ln(x/(x-11))=ln(3)
To fulfill this condition the arguments of the logarithm must be equal:
x/x-11=3
<=> x=3x-33
<=> x=16.5
2007-01-22 01:46:47 · answer #1 · answered by schmiso 7 · 0⤊ 0⤋
ln x -ln{x-11} = ln 3 or
ln(x/(x - 1)) = ln 3 which leads to x/(x - 1) = 3
or x = 3x- 3 or 2x = 3 which leads to:
Answer: x = 3/2 =1.5
2007-01-22 02:32:53 · answer #2 · answered by Anonymous · 0⤊ 0⤋
lnx - ln(x-11) = ln ((x/(x-11)) =ln 3 x>11
(x)/(x-11) =3 x= 3x-33 ===> x= 33/2
2007-01-22 05:04:28 · answer #3 · answered by santmann2002 7 · 0⤊ 0⤋
ln(x) - ln(x-11) = ln(3)
x/(x-11) = 3
x = 3(x - 11)
x = 3x - 33
-2x = -33
x = 33/2 = 16.5
2007-01-22 01:41:29 · answer #4 · answered by Dave 6 · 0⤊ 0⤋
Next time try to make your homework by yourself, instead of fooling someone on the web.
But anyway, the equation is false.
2007-01-22 01:39:15 · answer #5 · answered by Ari 2 · 0⤊ 3⤋
x= 16.5
2007-01-22 02:01:58 · answer #6 · answered by ag_iitkgp 7 · 0⤊ 0⤋