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It takes 12 units of carbohydrates & 6 units of protein to satisfy the minimum weekly nutrition requirements of one certain species of animal in the Houston Zoo. A particular type of meat contains 2 units of carbohydrates and 2 units of protein per pound while particular type of cheese contains 3 units of carbohydrates and 1 unit of protein per pound. Meat costs $3.50 per pound, cheese costs $4.50 per pound.

(a) How many pounds of each are needed to minimize the cost and still meet the minimum requirements for proper nutrition?

(b) What is this minimum cost of food per week?

2007-01-22 00:17:02 · 2 answers · asked by mozzarella_24 2 in Education & Reference Homework Help

What is the answer to the problem?

2007-01-22 01:20:22 · update #1

2 answers

Objective: Minimize 3.50m + 4.50c
Constraints:
Carbohydrates ... 2m + 3c >= 12
Protein ... 2p + 1c >= 6
(and the trivial constraints ... m >=0 and c >=0)

The minimum value will most likely occur at the point of intersection of the two main constraints. You need to find that point. You can find the minimum cost by plugging your numbers into the objective formula.

(Note: In theory the minimum value could also occur at the intersection of either constrain and the places where m or c = 0.)

2007-01-22 00:24:10 · answer #1 · answered by dmb 5 · 0 0

A-25
B- 35

Justin

2007-01-22 10:43:38 · answer #2 · answered by Anonymous · 0 0

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