2007-01-21 22:17:12 · 12 answers · asked by tocatchtheuncatchableii 3 in Science & Mathematics ➔ Mathematics
56 = 2^3 * 7
70 = 2 * 5 * 7
HCF is calculating by multiplying common exponential of each prime number
i.e. 2 * 7 = 14
2007-01-21 22:22:29 · answer #1 · answered by Tom :: Athier than Thou 6 · 1⤊ 1⤋
2 x 2 x 2 x 7 = 56
2 x 5 x 7 = 70
therefore HCF of 56 & 70 = 2 x 7= 14
2007-01-28 18:46:40 · answer #2 · answered by Sir Jas 2 · 0⤊ 0⤋
The answer would be 14. The reason for this is because you first have to break down both numbers into products of prime factors. 56 would be 2x2x2x7 and 70 would be 2x5x7. Remember that prime numbers are numbers that can be divided evenly by just two integers. That number itself and one.
So, then you follow this. You find which numbers appear in both sets of prime factors. In this case 2 and 7. Then, you find which set has these numbers appear the fewest amount of times. This case, you'd use the 70 set for 2, since 2 appears the fewest amount of times in this set, and the 70 set for 5 also, for the same reason as above, but for the number 7.
Then, for your final step, you take the 2 and 7 and multiply them, therefore getting your HCF, 14.
This procedure works for all number sets when your looking for the HCF of those numbers.
There you go. :) Hope I helped.
2007-01-27 17:00:39 · answer #3 · answered by iamanicecaringfriend 3 · 0⤊ 0⤋
Common Factors Of 56 And 70
2017-01-14 03:50:55 · answer #4 · answered by ? 4 · 0⤊ 0⤋
56 = 2 x 2 x 2 x 7
70 = 2 x 5 x 7
therefore HCF of 56 & 70 = 2 x 7= 14
2007-01-21 22:26:18 · answer #5 · answered by Anonymous · 1⤊ 0⤋
To find the HCF without factoring either number, use the Euclidean algorithm.
70/56 = 1 remainder 14
56/14 = 4 remainder 0
since the remainder was zero, the HCF is 14
The original Euclidean algorithm uses subtraction:
70-56 = 14
56-14 = 28
28-14 = 14
14 = 14, so 14 is the HCF
2007-01-26 10:22:10 · answer #6 · answered by rpresser 2 · 0⤊ 0⤋
One way to do this is to find all the prime factors of each nuimber, pick out the common ones and multiply them together.
56 = 2 x 2 x 2 x 7
70 = 2 x 5 x 7
The only prime factors in common are 2 and 7, so the highest common factor is 2 x 7 which is 14.
2007-01-21 22:22:31 · answer #7 · answered by Gnomon 6 · 1⤊ 0⤋
56 | 70 » 2
28 | 35 » 7
4 | 5 14
56 70
14 14
2007-01-27 12:39:29 · answer #8 · answered by quasar 1 · 0⤊ 0⤋
56=2^3*7 70=2*5*7 HCF= 2^3*3*5*7=840
2007-01-21 22:26:11 · answer #9 · answered by santmann2002 7 · 0⤊ 2⤋
the hfc of 70 is 2, 5, 7
2013-10-02 07:29:04 · answer #10 · answered by Bukola Aibinu 1 · 0⤊ 0⤋