vic is 28 years older than jan.twelve years ago he was eight times as old as jan.find their present ages.?

Answer 1

J is 16, and V is 44

Twleve years ago....

V = Vics age
J = Jans age

V - 28 = J (Vic was 28 years older that Jan)

V = 8J (Vic was 8 times as old as J)

8J - 28 = J (Substution of 8J for V)

7J = 28

J = 4

That was 12 years ago....

Today, J is 16, and V is 44

Answer 2

let be v the age of vic and j the age of jan

now , we can write v =28+j (1)

12 years ago, the age of vic was v-12 and of jan j-12

and v-12 = 8(j-12) =8j -96 or v= 8j-84 (2)

so, we have two sets of equations (1) and (2)

we solve as

28+j = 8j -84 or 7j = 112

so j=16 and vic 44

12 years ago they were old 4 and 32

Answer 3

v = j + 28

v - 12 = 8 * (j - 12)

v - 12 = 8j - 96

v + 84 = 8j

substitute v ...

j + 28 + 84 = 8j

j + 112 = 8j

112 = 7j, j = 16

solve for v, v = 16 + 28 = 44

j = 16, v = 44

Answer 4

v = j + 28

(v - 12) = 8(j - 12)
v - 12 = 8j - 96
v + 84 = 8j

Using substitution

(j + 28) + 84 = 8j
j + 112 = 8j
112 = 7j
j = 16

v = 16 + 28
v = 44

Vic is 44, Jan is 16
------------------
Check:

44 = 16 + 28
44 = 44 correct

44 + 84 = 8 * 16
128 = 128 correct

Answer 5

V = 28 + J

V -12 = 8 * (J-12)
therefore solving
J=16
V=44

Answer 6

vic 44
jan 16

Answer 7

victor = jan + 28

victor - 12 = 8 * ( jan - 12 )

jan + 28 - 12 = 8 ( jan - 12 )
jan + 16 = 8 jan - 96
7 jan = 112
jan = 16
victor = 44

If victor engages in sexual relations with Jan it would technically be illegal. And now you know!

Answer 8

v, j
v=j+28
v-12, j-12
v-12=8(j-12)
v=8j-84
=>7j=112
j=16
v=44