What is the value of 121 base 4 + 84 base 16 and explain it?

Answer 1

If you convert both to decimal you get:

(1*16+2*4+1*1) + (8*16 + 4*1) = 157 in decimal

If you want to leave them in base 16, then 121 in base four is 19 in base 16. So the same is 19+84 = 9D in base sixteen, since D is the digit for 13 in base 16.

You could also convert the second number to base 4 to get 2010 base 4. Then adding the two numbers in base 4 would give you:
121 + 2010 = 2131 base 4.

Answer 2

The easiest thing to do is first convert those two numbers to base ten. 121 base ten is the same as (working left to right with the digits) 1*(4)^2+2*(4)^1+1*(4)^0 whish is equivalant to 1*16+2*4+1*1...which is 16+8+1, or 25. Do the same thing with 84 base 16, and you'll get 8*(16)^1 + 4*(16)^0, which is 128+4=132. now we have both numbers in the same base (the one we are most familiar with, base 10) so all we have to do is add them. 25+132=157. (Please note my math might be a bit off, it's 3am...but this is how you would solve it.)

Answer 3

i think that u r asking whats the value of
121/4 + 84/16
for this u must take the lcm of denominator
i.e. for 4 and 16 the lcm is 16
then u must put this in the numerator like this
something/16
then u must divide the denominator of both fractions with this one by one
i.e. dividing 4 by 16 of 121/4 gives 4
similarly dividing 16 by 16 of 84/16 gives 1
now multiply these 4 and 1 with their numerators respectively
i.e. multiplying 121 by 4 gives 484
and multiplying 84 by 1 gives 84
add these two results i.e. 484+84 gives 568
this 568 will be the numerator of ur ans and lcm calculated abow will be the denominator
i.e.568/16 which can be rewritten as 71/2

Answer 4

(1*16+2*4+1*1)+
(8*16+4*1)

=25+132
=157
in base 10

Answer 5

121 base 4 = 1X4^2 + 2X4^1 + 1X4^0=25
84 base 16 = 8X16^1 + 4X16^0 = 132

132 + 25 = 157

Answer 6

21 base 4 + 84 base 16 makes no sense.
Probably it should be
log(21) base 4 + log(84) base 16.
Could be you wrote this as log [ (21) base 4 + (84) base 16 ] and this has no meaning, so it is wrong.

log(21) base 4 = log(21) / log(4) (base 10) = log(21-4) = log(17)
log(84) base 16 = log(84) / log(16) (base 10) = log(68)
Their sum equals
log(17) + log(68) = log(17 x 68) = log 1156 (base 10).

Th

Answer 7

what?