What is the distance between two points on a number line if the corrdinates of the points are
4+sq5 and 2 -sq5
please tell me the inside story.
2007-01-21 18:25:50 · 5 answers · asked by liangjizong22 1 in Science & Mathematics ➔ Geography
I assume you mean 4+√5 and 2-√5.
The distance is just (4+√5) - (2-√5)
= 4 + √5 - 2 - (-√5)
= 4 - 2 + √5 + √5
= 2 + 2√5.
2007-01-21 18:45:38 · answer #1 · answered by Scarlet Manuka 7 · 0⤊ 0⤋
4+sq5 means 4+25=29
and 2-sq5 means 2-25=-23
therefore the distance on number line=23+29=52
2007-01-22 02:38:47 · answer #2 · answered by speenzer 1 · 0⤊ 1⤋
Just subtract the second number from the first.
(4 + â5) - (2 - â5) = 2 + 2â5
2007-01-22 03:18:26 · answer #3 · answered by Northstar 7 · 0⤊ 0⤋
Distance
=[(4+sq5)²+(2-sq5)²]^1/2
This is the pythagoras formula.
2007-01-22 02:30:28 · answer #4 · answered by A 150 Days Of Flood 4 · 0⤊ 1⤋
The inside story is very complex, more than I can type here. First you can start with the equation: (3x*y(6-y)sq) if that doesn't help you, than you have probably figured out that I am drunk and feeding you a line of crap.
2007-01-22 02:37:30 · answer #5 · answered by Anonymous · 0⤊ 0⤋