my question is this 3a-2b=0 how can that even be right?

Question

it is on my army practice test

I meant to also put a+2 and b+3 so 3a-2b is 0 how is that even right?

a=2 and b=3

Answer 1

You have to express one variable in terms of the other:

Start: 3a - 2b = 0
Add 2b to each side of the expression: 3a = 2b
Divide each side of the expression by 3: a = 2/3(b)

So, the answer for any value a is a value of b that is 1.5 times a.

a = 2, b = 3
a = 4, b = 6
etc.

This is first year Algebra. If you didn't see it in school you should pick up a high school text book or computer program that teaches it if you want to do well on your test.

Answer 2

a=2 b=3

Answer 3

3a - 2b = 0
substitute a = 2

sustitute b = 3

3(2) - 2(3) = 0

6 - 6 = 0

Answer 4

If a=0 and b=0

Answer 5

It can be right if, for any values of a and b, the ratio a/b = 2/3, or b/a = 3/2.

3a - 2b = 0 ---> 3a = 2b ---> a/b = 2/3 or b/a = 3/2

Answer 6

If you do it like this:
3a = 2b
and then
(3/2)a = b
it means that whatever b is, a is always going to be 3/2 of that number. Either that or a and b are both equal to 0.

Answer 7

3a-2b=0

3-3+2-2=0

Answer 8

Look at the quetionnaire again. The question and answer may be right if a & b have equivalent figure; Example if "a" is equivalent to 2, & "b" is 3; THEN: 3(2)-2(3) equals 6-6 which is 0.

Answer 9

(a=0, b=0) or (a=2, b=3)

Answer 10

3(2) - 2(3) = 0

6 - 6 = 0

That means that a = 2
and
b = 3
or

any ratio of these numbers like a = 10 and b = 15
or they both = 0