Balance an equation.?

Question

K4Fe(CN)6 + KMnO4 + H2So4 --> KHSO4 + Fe2(SO4)3 + MnSo4 + HNO3 + CO2 + H2O.

the numbers are actually small subscripts. Kay! thanks!

Answer 1

2K4Fe(CN)6 + KMnO4 + 13H2So4 --> 9KHSO4 + Fe2(SO4)3 + MnSo4 + 12HNO3 + 12CO2 + H2O

Answer 2

I get...

10 K4Fe(CN)6 + 122 KMnO4 + 299 H2SO4 reacts to form
162 KHSO4 + 5 Fe2(SO4)3 + 122 MnSO4 + 60 HNO3 + 60 CO2 + 188 H2O, assuming I understood your formula correctly.
...
Hm, I might have miscounted oxygen; the previous answer has much prettier numbers!
...
No, I think borscht miscounted oxygen. You decide.

Re: equation balancer. Do they have those? It would make sense, I guess. This is how I did it:
I said there were x of K4Fe(CN)6, y of KMnO4, and z of H2SO4. (Well, I actually used a, b, and c, but then c started looking like C and I just think xyz is a better choice.)

I then started tracing atoms from left to right. For instance, there are 4 K's in each of the K4Fe(CN)6 molecules (of which there are x), so these contribute 4x potassium. Likewise, the KMnO4 contribute y potassium, for a total of 4x+y. The only K on the right side is in KHSO4. So, there must be 4x+y of that molecule. Etc. Eventually you have coefficients in front of every molecule, even though you haven't finished tracing all the atoms. I think I did K, Fe, C, N, and Mn first, filling out all the coefficients. Then I traced S. There's a supply of z S's from the z H2SO4 on the left. S gets used by the (4x+y) KHSO4's, the (x/2) Fe2(SO4)3's, and the (y) MnSO4's, so this gives me the equation

z = 4x + y + 3x/2 + y

And so on. With only three unknowns, you need only three of these equations before the whole problem turns solvable.

There's a nice connection to number theory buried in here somewhere, but it's been obscured by the complexity of the reaction.

Answer 3

This is the ugliest one of these that I have ever seen. I have spent too much time on it without getting a satisfactory answer. The way to do this one is to put an algebraic coefficient in front of every constituent on each side, and then develop nine equations in the nine unknowns by counting what atoms go into each side. The work can be eased by representing H2SO4 as H+ and SO4--, and this will permit removing several common factors.

Answer 4

doc B is a cheaper he used an equation balancer to solver it


ok docB i will have to verify your explanation later but here is the site to solve this equation.

http//www.nitrogenorder.org/cgi-bin/balance.cgi

click on the advanced version and just plug in your equation

Answer 5

Don't forget to carry the 9.