A farmer wishes to enclose a rectangular region with 210 m of fencing in such a way that the length is twice the width and the region is divided into two equal parts. What length and width should be used?
2007-01-21 16:25:52 · 3 answers · asked by World Expert 1 in Education & Reference ➔ Homework Help
P.S. I have to first put this into an equation, then solve.
2007-01-21 16:28:01 · update #1
What this is saying is that there will be 2 lengths and 3 widths (one width in the middle to divide the whole into 2 parts).
We know that length = 2 widths
and we know the total of all of them is 210 meters.
Here are 2 equations:
L= 2W
2L + 3W = 210
Now substitute
2 (2W) + 3 W = 210
7 W = 210
So the width is 30 meters
and length is twice that or, 60 meters
2007-01-21 16:32:35 · answer #1 · answered by ignoramus 7 · 1⤊ 0⤋
I think ignoramus has made a mistake.
Suppose that the width is x, this would make the lengh 2x (since the lenght is twice the width). Knowing that the formula for a perimeter is 2 x lenght + 2 x width. This would put the formula as:
2 x + 4 x = 210
6 x = 210
x = 35
Means that the lenght is 70 and the width is 35
Good luck
2007-01-22 00:34:00 · answer #2 · answered by Twin Peak 3 · 0⤊ 0⤋
Let width be 'x', length will then be '2x
x + 2x = 3x
3x = 210
x = 70
70 / 2 =35
210 / 2 = 105
70 ( length ) + 35 ( width ) + 105
2007-01-22 00:41:29 · answer #3 · answered by Anonymous · 0⤊ 0⤋