A car accelerates uniformly and reaches a speed V of 3.40 m/s in 8.00 seconds. Calculate the distance traveled by the car from a time of 0.30 to 7.00 seconds.
Ok, so I calculated the acceleration to be 0.425 m/s^2, but I am not sure which motion equation to use because I keep getting the wrong answer.
Thanks for any help.
2007-01-21 16:17:03 · 2 answers · asked by Defcon6 2 in Science & Mathematics ➔ Physics
My online questionnaire is saying that 18.9 m is wrong; any other ideas?
2007-01-21 16:48:58 · update #1
You need to work out the distance travelled at 7 seconds, and the distance travelled at 0.3 seconds, and subtract one from the other. You use the equation s = ut + ½at². Since u is 0, the first part of the equation can be ignored. The answer is between 10 and 11.
2007-01-21 22:08:15 · answer #1 · answered by Ben C 2 · 0⤊ 0⤋
s = it+1/2 (at^2)
a => acceleration
t => time
s => distance
i => initial speed
Assume the car starts from a dead stop.
After 0.3 seconds it is going 0.425 * 0.3 = 1.4 m/s
The car is accelerating for 7.0 - 0.3 = 6.7 seconds.
s = 1.4 * 6.7 + 1/2(0.425 * 6.7 * 6.7)
s = 18.9 m.
2007-01-22 00:39:59 · answer #2 · answered by J C 5 · 0⤊ 0⤋