pls reduce?

Question

how can i reduce each rational expression to lowest terms?

(27)(y^3)-(27)(y^2)+(9)(y)-(1) /
(27)(y^3)-(1)


(4)(x^2)-(12)(x)(y)+(9)(y^2)-(16)(z^2) / (2)(x^2)-(3)(x)(y)(z)+(4)(x)(z^2)



(3)(a^2)(b)(c)+(a)(b^2)(c)-(2)(a)(b)(c^2) / (9)(a^2)-(b^2)+(4)(bc)-(4)(c^2)

Answer 1

Questions 2 and 3 got cut off.

For #1, the denominator factors using sum of cubes:

27y³ - 1 = (3y - 1)(9y² + 3y + 1)

And the second part is unfactorable, so if anything is going to factor, it will have to be 3y - 1.

+1/3 | +27 −27 +09 −01
- - - -| +00 +09 -06 +01
- - - - - - - - - - - - - - - - -
- - - -| +27 -18 +03 +00

So the numerator factors to:

(3y - 1)(27y² - 18y + 3) = 3(3y - 1)(9y² - 2y + 1)

Put so the (3y - 1) cancels, leaving you with:

3(9y² - 2y + 1)
- - - - - - - - - - -
(9y² + 3y + 1)

And that's as far as you can go....

Sorry I can't help with the rest unless you repost them.