Finding X in a triangle ( length) **Math**?

Question

I have a math problem that has me confused. I have to find the length of X in both simplified radical and decimal form

The triangles measure meants are "20" on the side next to the 90 degree angle. "15" on the bottom of the triangle. And (X) on the opposite side of the 90 degree angle.

PLEASE HELP !

Answer 1

since it has a 90 degree angle, it is a right triangle. meaning you can use pythagorean's theorem
where the two legs of the triangle a, b which in this case are 20 and 15
and the hypotenuse c in this case x are related in that
a^2 + b^2 = c^2
an easy way to do this is to know a pythagorean triple
3 4 5 is a triple that would help where the legs are 3 and 4 and the hypotenuse is 5
you know that 3*5 = 15
4*5 = 20
so 5*5 = X = 25
The two triangles are similar


Another way is to just stick in the numbers
15^2+20^2 = X^2
225 + 400 = X^2
625 = X^2
X is a length so it is positive
sqrt(625) = X
X = 25

Answer 2

Use Pythagoream's Theorem a2+B2=C2

(20*20)+(15*15)=c2
625=c2
25=c or in this case X

Answer 3

a^2 + b^2= c^2

Pythagorean theorem

aswer is 25

Answer 4

Look up pythagorean's theorem, that is how you will solve the question (can't do ur homework for you sorry :-P)