2007-01-21 14:24:13 · 4 answers · asked by john m 1 in Science & Mathematics ➔ Mathematics
x=3
2007-01-21 14:33:14 · answer #1 · answered by Beach_Bum 4 · 1⤊ 0⤋
3*sqrt(x - 2) = 3
Dividing both sides by 3
sqrt(x - 2) = 1
Squaring both sides
x - 2 = 1
Adding 3 to both sides
x = 3
There is no extraneous solution as x = 3 satisfies the equation
2007-01-21 22:28:52 · answer #2 · answered by Sheen 4 · 1⤊ 0⤋
3sqrt(x - 2) = 3
Your first step would be to divide both sides by 3.
sqrt(x - 2) = 1
Now, square both sides, to get rid of the radical.
x - 2 = 1
Solve as normal.
x = 3
We can't assume this value will work, so we plug it back into our original equation, 3sqrt(x - 2) = 3.
LHS = 3sqrt(3 - 2) = 3sqrt(1) = 3(1) = 3
RHS = 3
LHS = RHS, so x = 3 works.
Therefoure, our solution is x = 3.
2007-01-21 22:27:52 · answer #3 · answered by Puggy 7 · 2⤊ 0⤋
Square both sides:
9(x-2)=9
9x-18=9
9x=27
x=3
Check:
3*(â3-2)=3
3(1)=3
3=3
2007-01-21 22:31:21 · answer #4 · answered by Anonymous · 0⤊ 0⤋