V24 = V4 times V6 = 2 times V6; 3 times this is 6 V6
V96 = V16 times V6 = 4 times V6; 2 times this is 8 V6
So 6V6 - 8V6 = -2V6
2007-01-21 14:16:29
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answer #1
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answered by hayharbr 7
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Defining 3V24 is equal to 3 x sqrt(24).
By knowing that 96/4 = 24, sqrt(96) = sqrt(24x4).
Therefore, sqrt(24x4) = sqrt(4) x sqrt(24) = 2sqrt(24).
Now, use U-subtitution or "A x sqrt(x) + B x sqrt(x) = (A+B)[sqrt(x)]".
Let U= sqrt(24) ;
3sqrt(24) - 2sqrt(96) = 3U - 2x2sqrt(24) = 3U - 4U = -1U.
-1U = -1[sqrt(24)].
A[sqrt(x)] + B[sqrt(x)] = (A+B)[sqrt(x)].
3sqrt(24) - 2sqrt(96) =
3sqrt(24) - 2 x [2 x sqrt(24)] =
3sqrt(24) - 4sqrt(24) =
(3-4)[sqrt(24)] =
-1[sqrt(24)].
sqrt(24) = sqrt(6 x 4) = 2sqrt(6)
-1[sqrt(24)] = -2[sqrt(6)]
sqrt(6) is approximately 2.45.
-2[sqrt(6)] is approximately -4.9.
2007-01-21 22:34:31
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answer #2
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answered by c0ol S 1
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3â4*6-2â16*6
3*2â6-2*4â6
6â6-8â6
-2â6
2007-01-21 22:26:55
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answer #3
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answered by Anonymous
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3sqrt(24) - 2sqrt(96)
3sqrt(4 * 6) - 2sqrt(16 * 6)
6sqrt(6) - 8sqrt(6)
since both of these have the same sqrt value
(6 - 8)sqrt(6) = -2sqrt(6)
ANS : -2sqrt(6)
2007-01-21 23:34:42
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answer #4
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answered by Sherman81 6
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-6.913459
EDIT: I can solve it so it's not in decimal format... working on that right now!
(2)3V3 - (4)2V6
2007-01-21 22:14:16
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answer #5
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answered by Anonymous
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V96=V(4x24)=V4V24=2V24 so 3V24-2V96=3V24-4V24= -V24= -2V6.
2007-01-21 22:18:26
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answer #6
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answered by zee_prime 6
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'log' both sides log 3V24=log2V96
maybe...I'm not really sure
2007-01-21 22:21:10
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answer #7
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answered by Anonymous
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-2V6
2007-01-21 22:15:20
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answer #8
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answered by na 2
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