A sample of 9.00 g of aluminum metal is added to an excess of hydrochloric acid.
2007-01-21 13:43:56 · 3 answers · asked by tortuga_gp08 1 in Science & Mathematics ➔ Chemistry
Holy Smokes! My head hurts now...stop it!
2007-01-21 13:46:42 · answer #1 · answered by Greed...Is Good 3 · 0⤊ 0⤋
Write the equation
Al + 3HCl -> AlCl3+ 1.5 H2 (elemental hydrogen is diatomic)
Each mole of Al converted produces 1.5 moles of H2
9 g of Al = 1/3 mole of Al
So we produce 1.5 x 1/3 or 0.5 moles of H2
Since at STP, 1 mole of "ideal gas" has a volume of 22.4L
0.5 moles will have a volume of 11.2 L
2007-01-21 21:50:32 · answer #2 · answered by cattbarf 7 · 0⤊ 0⤋
Convert 9g of aluminum to moles. 2 moles of Al make 3 moles of hydrogen gas. Then use the ideal gas law PV=nRT and solve for volume.
2007-01-21 21:50:12 · answer #3 · answered by LGuard332 2 · 0⤊ 0⤋