Please help me with a problem I already have the answer to but I just can't seem to figure out how I go it.

Question

A line passes through the points (0,-1) and (2,3). What is the equation for the line?(Please show or tell me how to arrive at the answer. By the way here goes the answer) Answer: The equation for the line is y+ 2x-1.

Answer 1

m=(3-(-1))/(2-0)=4/2=2 slope
using the point (0,-1):
y-(-1)=2(x-0)
y+1=2x
y=2x-1 /

Answer 2

i think it is y = 2x -1 not y+2x-1 :))


(1) with 2 points you can get the line's slope by

m = (y2 - y1)/(x2 - x1)
m = [3 - (-1)]/ (2-0) = 4/2
m = 2

(2) use slope-intercept form,
y = mx +b

*use either of the two points to find 'b'.
*using point (0,-1), you get
-1 = 2(0) + b
b = -1

(3) going back to slope-intercept form and substituting b = -1 and
m = 2,

y = mx + b
y = (2)x + (-1)
y = 2x -1

Answer 3

m=(3-(-1))/(2-0)=4/2=2 slope equation

Use the point (0,-1) and point-slope form

y-(-1)=2(x-0)
y+1=2x
y=2x-1

Answer 4

I agree. I recognized the typo, using + instead of =.