3xy^2 - 5yz = 4x
This becomes
3xy^2 - 4x = 5yz
This becomes
x(3y^2 - 4) = 5yz
This becomes
x = (5yz)/(3y^2 - 4)
HTH
Charles
2007-01-21 12:57:12
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answer #1
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answered by Charles 6
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3xy^2 - 5yz = 4x
3xy^2 -4x = 5yz
x(3y^2-4) = 5yz
x = 5yz/(3y^2-4)
2007-01-21 20:56:44
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answer #2
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answered by Steve A 7
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3xy^2 - 5yz= 4x subtract 3xy^2 from each side
-5yz=4x-3xy^2 factor out x on RHS
-5yz=x(4-3y^2) divide both sides bt 4-3y^2
x=-5yz/(4-3y^2) or
x=5yz/(3y^2-4)
2007-01-21 21:26:35
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answer #3
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answered by yupchagee 7
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x=5
2007-01-21 21:01:20
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answer #4
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answered by whitelampshade 2
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x = 5z / 3y^2 - 4
2007-01-21 21:00:54
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answer #5
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answered by katie f 3
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Absolutely I can. Will I do your homework for you? No.
2007-01-21 20:56:11
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answer #6
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answered by Walker 2
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it took me a while but this is what i got
0.45+z=x
2007-01-21 21:02:04
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answer #7
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answered by JUDI 3
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no
2007-01-21 20:56:35
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answer #8
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answered by Anonymous
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