urgent chemistry help needed please !!!!!!!!?

Question

This is my equation-NaHCO3+HCl ----> NaCl +H2O+CO2
Sodium hydrogen carbonte -3.00 grams
Sodium chloride - 1.15 grams
1)how do u calculate the number of moles for these masses and find the % yield
2)what is the balanced equation of calcium carbonate and hydrochloric acid
please help me to do this .....really appreciate any help
THANK YOU !!!

Answer 1

It is often best to start by balancing the equation. However, this one appears to be balanced already.

You can calculate the moles of NaHCO3 and NaCl by dividing the masses given by the molecular weight of the compound.

Example, the molecular weight of NaCl is equal to the molecular weights of Sodium and Chlorine (from the periodic table, many are available online, Na = 22.98, Cl = 35.45) so NaCl = 58.43

1.15 grams NaCl / (58.3 grams NaCl/mol NaCl)=
.01968 moles NaCl

You do the same kind of calculation and find out how many moles is represented by NaHCO3
The molecular weight should be near 84 gm/mole, but you need to look up Hydrogen, Carbon, and Oxygen and get the exact weights. Don't forget that there are three oxygen atoms.

The % yield is found by figuring out how many of the moles of NaHCO3 became a mole of NaCl. The expression:

100* (moles of NaCl made/ moles NaHCO3 used)

gives the % yield.

Good luck. This kind of calculation is the basis for hands-on chemistry work.