Think of any fundamental operation(addition, subtraction, multiplication, division, exponentiation) on
A. Irrational number, which results in:
- a rational number
- an irrational number
B. A complex number( a+bi, where a and b are real and b is not equal to zero), which results in:
- a real number
-a complex number (a+bi, where a and b are real)
I need some examples with numbers, I am stuck on this. Please help.
2007-01-21 12:28:57 · 5 answers · asked by ruthnsnare 2 in Science & Mathematics ➔ Mathematics
A. part a. square root of 6 times the square root of 6 = 6 (rational number)
part b. 3 times pi = 3pi (irrational)
or
square root of 7 plus the square root of 7 = square root of 14
B. part a. (3+2i)(3-2i)= 9+6i-6i-4isquared = 9 +6i - 6i +4= 13
part b. (9+7i) - (6+2i) = 3 + 5i
2007-01-21 12:44:28 · answer #1 · answered by soxnut726 2 · 0⤊ 0⤋
A rational number 1 devided by 2 -- 1/2
irrational number 4 devided by 2 -- 2
2007-01-21 12:38:42 · answer #2 · answered by Anonymous · 0⤊ 0⤋
(sqrt 3) ^ 2 = 3...irrational ----> rational
(2 + 3i) (2 -3i) = 4+9 = 13......irrational ------> rational
2007-01-21 12:46:12 · answer #3 · answered by davidosterberg1 6 · 0⤊ 0⤋
hi chum this an elementary question in keeping with linear equations you ought to use transposition approach in this methodology while a term is transfered from one area to different its sign turns into opposite answer: x+4-7x=22 =4-7x=22-x (right here x comes from the left area its sign variations) =4=22-x+7x(right here 7x comes from the left area its sign variations) =4-22=6x(same) =-18=6x x=-18/6 =-3 Bye Bye!!!!!!!!!!!!!!!!!!!!!!
2016-10-31 23:00:29 · answer #4 · answered by Anonymous · 0⤊ 0⤋
A) i^2 = -1
i*2 = 2i
B) (5+4i) - 4i = 5
(5+4i)*2 = 10+8i
2007-01-21 12:40:12 · answer #5 · answered by Steve A 7 · 0⤊ 0⤋