Find the length of each side of the rectangle so that it has the given perimeter. p=50
w=2x-5
L=x
2007-01-21 12:17:11 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
p = 2L + 2W
50 = 2x + 2 (x-5)
50 = 2x + 2x - 10
60 = 4x
x = 60/4
ANSWER
x = 15 units
2007-01-21 13:08:54 · answer #1 · answered by swas77 2 · 0⤊ 0⤋
p = 2w+2L
50=2(2x-5) +2x
50 = 4x -10 +2x
50 = 6x-10
60 = 6x
10 = x = length
2x-5 = 15 = width
I see your problem. The width is greater than the length is your concern. However it really does not matter which dimension you call width and which you call length. It is a judgement call.
If you stand i front of a house and see that the distance from one side to the other is 100 feet, do you say the house is 100 feet wide or 100 feet long?
2007-01-21 20:35:48 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
First notice that the rectangle has two pairs of equal sides.
So 2x - 5 + 2x - 5 + x + x = 50
Thats a total of 6x - 10 = 50
So 6x = 60 which means x = 10
2007-01-21 20:21:24 · answer #3 · answered by hayharbr 7 · 0⤊ 0⤋
P = 2L + 2w
=50 = 2x + 4x - 10 ==> 6x = 60 ==> x = 10, w = 15
2007-01-21 20:21:35 · answer #4 · answered by mjatthebeeb 3 · 0⤊ 0⤋